[FR] Extend --replace

[NightMachinery]

I want to both print a highlighted version of the text a la rg --passthru ... and further process matches. Currently this needs two calls of rg. If --replace supported something like $1:$LINE, I could just run a cut -d: -f1 and cut -d: -f2-1 to get the data, with just one rg call. This should perform better if there are lots of non-matching lines? ... Anyways I think it's a good feature to have.

Perhaps a better option is to add --exec that execs a command? Sth in the spirit of --exec 'cp $1 ~/tmp'.

[okdana]

I don't know about the --exec thing (doubt he'll go for that), but for the $LINE thing, you're just asking for this, aren't you?

% rg -r '$1:$0' '(foo) .+' <<< 'foo bar'
foo:foo bar

[BurntSushi]

I'm not sure I understand the problem here. @NightMachinary Could you please provide a more detailed example with inputs and outputs?

(But yeah, I am unlikely to add an --exec flag or enrich the --replace language.)

[NightMachinery]

@okdana That $0 should be added to the manpage.
@BurntSushi The --replace functionality I wanted is this $0 which is already there. :)
The --exec flag would be something just like --replace, but instead of printing the output you call $SHELL -c $OUTPUT_HERE. It's actually pretty easy to implement since you have the --replace part down already.